#14 백준 파이썬 [2839] 설탕 배달

#14 백준[2839] 설탕 배달

https://www.acmicpc.net/problem/2839

#14 [2839] Solution

-Easy Coding

order = int(input())

if order % 5 == 0:
    print(order // 5)

elif order % 5 == 3:
    print(order // 5 + 1)

elif order // 5 - 1 >= 0 and order - (5 * (order // 5 - 1)) == 6:
    print((order // 5 - 1) + 2)

elif order // 5 - 1 >= 0 and order - (5 * (order // 5 - 1)) == 9:
    print((order // 5 - 1) + 3)

elif order // 5 - 2 >= 0 and order - (5 * (order // 5 - 2)) == 12:
    print((order // 5 - 2) + 4)

else:
    print(-1)

-Short Coding

order = int(input())
three = 0
five = order//5
order %= 5

while five >=0:
    if order % 3 ==0:
        three = order//3
        order %= 3;
        break
    five -= 1
    order += 5
print(order==0 and (three + five) or -1)